Instrumentation & Measurement Magazine 24-4 - 106

where PkT
' is PkT
per unit
length of the PCA; and I is
the maximum value of the
PCA current.
The length of the PCA at
the common section (Lcom
)
is about 10 mm, which is
the same as rcom
. The conFig.
1. Diagram of the train passing through the neutral section.
separated from the power line because of the uneven line, resulting
in the PCA. The reason for generating the PCA at the
neutral sections is that the power supply line must be changed
to meet the three-phase power supply of the high-speed train.
When the train passes through the neutral line, the pantograph
must be separated from the power supply line, as shown in
Fig. 1. Firstly, the pantograph is separated from the A-phase
power supply line and connected to the neutral line. Then, it
separated from the neutral line and connected to the B-phase
power supply line. The PCA is produced in this process.
Reasons for the Influence of Train Speed on PCA
Radiation
The diameter (d) and the convective power (Pk
be changed because of the train speed (v). Besides, Pk
the PkT and PkL
vective power of the PCA
at common sections (Pk(com)
can be obtained by (1):
)
P PP Lcom
k(com)   
=

kT kT
1.892 ( 36)
I 
(2)
where Pk(com) and the radiation power (Ps(com)) of the PCA at the
common sections account for approximately 80% and 20% of
the total dissipative power (Ploss(com)
and Ps(com)
), respectively. So Ploss(com)
of the PCA at the common sections are:
()
P
and
) of the PCA will
includes
which generated by the transverse arc blowing
and the longitudinal arc blowing, respectively [17]. For the
PCA generated at the common sections, the distance between
the pantograph and the power supply line (rcom
) is short. Thus,
only PkT exists because the PCA is almost vertical, as shown in
Fig. 2.
PkT
of the PCA can be obtained by [18]-[20]:
kT
PI
 
0.1892 ( 36)

PP I 
s com
loss com
() 
()  20% 0.473 ( 36)
(4)
For the PCA generated at the neutral sections, the distance
between the pantograph and the power supply line (rneu
long. Both PkT and PkL
exist because the PCA has an angle with
the horizontal plane, as shown in Fig. 3. v' is the component of
v on the vertical plane.
Based on the simulation and measurement data from [21],
[22], the relationship between rneu and Lneu
can be calculated:
(1)
Lr v +0.952v  5.644
neu  
neu
v' can be derived by Fig. 3 and (5):
v 
[24]:
PI  0.1537
kL
v 
Fig. 2. Diagram of the PCA generated at the common section.
139.43
v
Similar to the calculation of Ps(com)
(7)
, we can obtain the con)
after
vective power of the PCA at the neutral sections (Pk(neu)
introducing PkL into (2) and further derive the radiation power
(Ps(neu)) of the PCA at the neutral sections:
P()s neu  0.25 0.1892( 36)+0.1537

I
 v +0.952 5.644 1
1.828 04 2
v 
The values of E at different distances from the PCA are unFig.
3. Diagram of the PCA generated at the neutral section.
106
equal. According to (4) and (8), E at 10 m away from the PCA at
the common or neutral sections (E10(com/neu)
) can be derived by:
IEEE Instrumentation & Measurement Magazine
June 2021




v
v 139.43
(8)
15
v
(6)
PkL of the PCA at the neutral section be calculated by [23],
4 1.828 10 42
(5)
) is
p
loss com
() 
80%
k com
(3)
Instrumentation & Measurement Magazine 24-4

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